Not positive of this:
5 C 2 = 10 ways for the two balls to match their boxes
the remaining 3 boxes can only have balls distributed to them in TWO ways (Out of a possible 6) where they do not match their boxes
10 * 2 = 20 ways for exactly two to match
Time to work = distance / rate = d/50
Time from work = d/75
total distance = 2d
total distance / total time = average rate
2d / (d/50 + d/75) = 2 / ( 1/50 + 1/75) = 2 / (3/150 + 2/150) = 2/ (5/150) = 300/5 = 60 m/hr ( as Chris found via different method !)
Parabola with vertex -3,-2
Vertex form y = a (x+3)^2 - 2 choose point (-1,0) when x = -1 y = 0 shows a = 1/2
y = 1/2 (x+3)^2 -2 expand
y = 1/2 x^2 +3x + 2.5 1/2 x 3 x 2.5 = 3.75 ( as EL found via a different method !)
Good to know in my everyday life ..... haha Thanx ! ~ EP
THAT is a really obscure law I did NOT know about !!
1+2+3+4 = 10 balls are accounted for already ...this leaves 2 balls to distribute
there are 4 ways to put the two in ONE box
there are 6 ways to distribute One and One ball amongst the four boxes
10 ways (I think)
xy = b sub in the point given
2*8 = b = 16
y = a x^2 + b sub in the point given....and b
8 = a (2^2) + 16
8 = 4a + 16
-8 = 4a
a = -2
-2,16
The domain is the scope of the 'x' values [0,23] which represents years.
So the domain is 23 from 0 inclusive represents years
https://web2.0calc.com/questions/our-club-has-10-members
y = yo + v0 t - 1/2 a t2 vo = initial velocity a = acceleration of gravity t = time
= 0 + 17.2 (0.5) - 12 (32)(0.52) = __________ meters
