https://web2.0calc.com/questions/clock-problem_3
pentagon has 5 sides
Distance / rate = time
Her ususal time is thus 30 m / 45 m/hr = 2/3 hr or 40 minutes
take away 15 minutes results in 25 minute travel time
distance /rate = time time will be 25 /60 of an hour
30 / rate = 25/60 hr
30 * 60/25 = rate = 72 m/hr
= x^2 + 10x+21 = 0 this is a bowl shaped parabola because the leading coefficient ( of x^2) is positive
the minimum will occur at the value of x = -b/2a
x = -10 / (2*1) = -5
Use this value of x in the equation to calculate the minumum value of the equation.......
LCM of 12 and 16 is 48
3 g / cm^3 * 1 kg / 1000 g * 100* 100 * 100 cm^3 / m^3 =
3 * 1 000 000 / 1000 = 3000 kg / m3
L1 3x+4y = - 14 is tha same as y = - 3/4 x - 14/4 slope, m = - 3/4 perpindicular slope is - 1/m = 4/3
Your new line L2 is thus y = 4/3 x + b sub in the point given to calculate 'b'
7 = 4/3 (-5) + b
so b = 13 2/3
y = 4/3 x + 13 2/3 Guest messed up with the slope ...it is not negative in the perpindicular line....
you can finish......
Agee! catmg method was pretty slick !
Melody.... I summed the 6 oclock time + 44 minutes for the hour hand....
You will need a calculator ...here are three ways to find ?
sin = opp/hyp arc sin ( 20/52)= ....... degrees
or
cos = adj/hyp arc cos (48/52) = ....... degrees
tan = opp/adj arc tan (20/48) = ....... degrees
