The highest peak of Mount Mitchell is 6,684 feet. If the radius of the Earth is 4000 miles, find the distance from this peak to a point on the horizon. Draw a diagram and round to the nearest mile. (1 mile = 5280 ft.)
6684 feet = 1.266 mile
hyp2 = leg12 + leg22
(4000 + 1.266)2 = leg12 + 40002 —> leg12 = (4001.266)2 – (4000)2
leg12 = 16,010,129.6 – 16,000,000
leg12 = 10,129.6
leg11 = sqrt(10,129.6)
leg11 = 100.6 mile
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