Percentages
Let's call X the original tuition, and let's assume it's greater than 10,000 so far. We'll analyze the first option:
Dean of Admissions suggests increasing tuition by 10% each year for the next two years. The first year the tuition would be. \(1.1x\)
The second-year the tuition would increase another 10% of the last amount, so it would end being. \(1.21x\)
Now for the second option:
The Provost suggests that each year they increase the tuition by 30% of the amount of the tuition above $10,000. The first increase would be \(0.3x-3000\)
And the new tuition at the end of the first year would be \(1.3x-3000\)
This new amount would be increased by applying the same rule, so the second-year increase would be 0.39x-3900
And the final tuition would be
1.69x - 6900
The Treasurer points out that the tuition will be the same under any scheme, so 1.69x - 6900= 1.21x
solve:
The actual tuition is $14,375
+363 