XxmathguyxX

\(6+b+c=15\)

\(36+b^2=c^2\)

\(c=\sqrt(36+b^2)\) that is 36 and b^2 in the square root

\(c=6+b\)

\(6+b+6+b=15\)

\(12+2b=15\)

\(2b=3\)

\(b=1.5\)

\(c=15-7.5\)

\(c=7.5\)

Someone check my work plz maybe it is wrong and guest got a different answer so idk whose is right

I'm giving this my best shot at it(tel me if i am wrong) Also befor i start. The problem said"Segments EG (which is a repeating decimal)" and "EG = 40"

40 is not a repeating decimal.

EG=40 

DC=27

40*27=1080

next,BC*FH=1080 and BC=AD=18

1080/18 = 60

FH=60

Just like geno3141!

And guest, in geno3141's answer, EG is smaller than AD

I believe the question has some error it says EG=40 and AD=18

AD is a hypotenuse of EG so....

x+3,11

I agree.

the first 4 numbers = 15/4

but 15/4 is not a whole number so it is impossible

\(1152\)

I think

1/3 = 50000

3/3 = 150000

1/4=150000

4/4=600000

1/5=600000

5/5=3000000

step by step explanation:

the angles on the inside of the pentagon=

\(180\times(5-2)=540\)

the angles on the inside of the trapezoid =

\(180\times(4-2)=360\)

7x360-360-540=

5x360-180=

1800-180=1620.

But we counted F and C as 360 + F and 360+c, so

1620-720=\(\boxed{900}\)

I agree

uh..... do you mean \(\frac{3}{4x}?\) or \(\frac{3}{4}x\)?

@Straight I got a different answer...

*0**

the first digit can be 5,6,7

the third digit can be 1-9

the fourth digit can be 1-9

3*9*9=243...

so 243+243+243=729?

tell me how i am wrong because i think i am