Vinculum

Hello Guest, 

This question has been answered by Melody in the link below (It looks like a great and detailed explanation):

https://web2.0calc.com/questions/confused_61

If you have any more question please let me know.

11* 10 is the smallest multiple of 11 that is greater than 100

and 11*9 is greatest multiple of 11 less than 100

110-99= 11

Expanding this would give us

$729x^6+1458ax^5+1215a^2x^4+540a^3x^3+135a^4x^2+18a^5x+a^6$

We know that the $x^4$ is $59535$

So, $1215a^2 = 59535$

Giving us $a^2=49$

$a=\sqrt{49},\:a=-\sqrt{49}$

$a=7,\:a=-7$

-Vinculum

Yep it was an error on my side

Thanks for catching it guys!!!!

Wait BuilderBoi

Who is right?

Hello, I agree

Here is the graph for proof:

https://www.desmos.com/calculator/ucqpddhlpo

a - 2b

(4 - 2i + 7)+2(3+2i-5i)

17-8i

-Vinculum

They are all the same because they all use a similar method:

It is the quickest way to solve it!!!

I hope you have a great day!

Just look at the question above and my work.

Look closely, Im sure you will understand.

If you have any questions let me know

SOHCAHTOA  for reference

Tan(theta) = 3/4

opposite/adjacent = 3/4

That means the opposite side is 3 and the adjacent side is 4

Using the Pythagorean Theorem

c = sqrt(3^2 + 4^2)

c = 5

cosine(theta): adjacent/hypotenuse

cosine(theta): 4/5

-Vinculum