Coordinates

$x^2+y^2-18x-14y+120=0$

Converting to standard circle equation:

$\left(x−a\right)^2+\left(y−b\right)^2=r^2$

$\left(x-9\right)^2+\left(y-7\right)^2=\left(\sqrt{10}\right)^2$

$center: (9, 7)$

$radius: \sqrt{10}$

-Vinculum

We can write

x^2  -18x  + y^2  -14y  =   -120               complete the square on  x and  y

x^2 -18x + 81  + y^2  -14y + 49  =  -120 + 81 + 49         factor and  simplify

(x - 9)^2 + ( y -7)^2  = 10

Center = (9, 7)

Radius  = sqrt (10)