Vinculum

I am not really understanding this question... So you are saying find f(2) if the function is 1/(1/sqrt(x+1))?

Triangle formula is (base*height)/2

Substituting these values into the formula gives us: (9*4)/2

=36/2 or 18

-Vinculum

A  conic section is just a plane curve, line, pair of intersecting lines, or point that is the intersection of or bounds the intersection of a plane and a cone with two nappes.

x = 25% gallon amount

.25 x   +  .12 (10)   =     .20 (10+x)

.05x = .8

x = 16 gal of 25% 

-Vinculum

Hello Jaelyn, 

The answer is true! The point, line, and pair of intersecting lines ARE special types of conic sections.

-Vinculum

Hallo, 

"Wie viel sind 10201938 Gramm in Kilo"

x gramm/1000 = kilogramm

10201938 gramm/1000 = 

10201.938 kilogramm

-Vinculum

Hello Jaelyn, 

Its simple, Hyperbola

-Vinculum

\(x=\tan \left(75^{\circ \:}\right)\cdot \:18\)

\(\tan \left(75^{\circ \:}\right)=2+\sqrt{3} \)

\(x=18\left(2+\sqrt{3}\right)\) or \(x=67.18\)

-Vinculum

Hello, 

\(\prod _{n=2}^8n\)

\(\prod _{n=2}^8a_n=a_2\cdot \:a_3\cdot \ldots \cdot \:a_8\)

\(a_2=2, a_3=3, a_4=4 ... a_8=8\)

\(2\cdot \:3\cdot \:4\cdot \:5\cdot \:6\cdot \:7\cdot \:8\)

\(40320\)

-Vinculum

Use section formula (x,y)=(mx2+nx1/m+n,my2+ny1/m+n) in which m:n are the ratio and (x1,y1) and (x2,y2)

are the points.

Let k:1

Substituting the values from the points mentioned above to (mx2+nx1/m+n,my2+ny1/m+n) gives 

(11,y)=(9k+15 / k+1,20k+5 / k+1)

Equate first component to get ratio:

​9k+15 / k+1=11

9k+15=11k+11

2k=4k

k=2

22:1​

Do the same for the second to get the value for y:

Calculation:

​y=20×2+5 / 2+1

=45/3

y=15​

-Vinculum