Solveit

1^0=1  but how the others became 0

i was thinking that there is more posibilities :P

yeah you are right !

cymath with free explonation:

hooh

wait .... :)

$\text{ let s say x y z is the digits of your 3 digit number } \\ xyz<500 \\x+y+z=13 \\x*y*z>30 \\\text{i am not divisible by five mean that your number cannot end with 0 or 5} \\ \text{so z cannot be 0 and 5 and your number less than 500 so x<5 x can be (3,1): } \\\text{there is only one number:} \text{ x=1 y=5 z=7 (157)}$

$\text{(show math as)} \rightarrow \text{(TeX commands) and it will show you a copiable text }$

$x+5-1+2-x=6 \\x-x+6=6\\6=6 \\ \text{of course 6 :)}$