\(\text{ (x+y=53) just put any x and y whose sum is 53 and you wil get the same answer as} 53^3\)
\((x+y)^3=(x+y)(x+y)(x+y)=x^3 + 3x^2y + 3xy^2 + y^3\)
Thanks CPhill and Guest !
\(m=\frac{y_2-y_1}{x_2-x_1}\)
why did you inverse it :)
Thanks Guest !
a+a+a=3a
570/38 = 15
Thanks CPhill and Melody !
yes 4 :)
original question:
http://web2.0calc.com/questions/second-trig-question-from-one-billion_1
