Solveit

P-pear

O-orange

A-apple

At a fruit stall, the price of a pear is 3/5 the price of an orange

P=3/5O  or 5P=3O

The price of an apple is half the price of a pear

A=1/2P or 2A=P

What is the ratio of the price of an orange to the price of an apple to the price of a pear?

O:P:A          
3:5

   1:2

 we need to have the same number of pear so

O:P:A                           O:P:A                           
3:5                                3:5:10

   1x5:2x5

only what you need to do it is translate words into numbers :)

b-bangles

r-rings

Sandy had some money:

some money is x

If she bought 5 bangles and 7 rings, she would have $3 left.

x-5b-7r=3

If she bought 7 bangles and 5 rings, she would need $5 more.

x-7b-5r=-5

So we have:

x-5b-7r=3

x-7b-5r=-5  

let s minus it from each other

x-5b-7r-(x-7b-5r)=3-(-5)

2b-2r=8

 If each bangle cost $8:

16-2r=8

r=4

Answer: 4

zero mutiplied by smthing will give you zero :)

So you need to find how can you make a zero:

2(x-3)(x^2+1)=0

x-3=0                                                           x^2+1=0

x=3                                                               x^2=-1

                                           since square CAN NOT be negative so that one is WRONG

Answer: x=3 

doesn t it need to be:

P(.775<z<.975)=infinity ?

i didn t understood can you explain me ? :D

if you are about my question below i mean letters like uknown s for example x or y

where is your equation ?

ax^2+bx+c

n*m=c

n+m=b

and you have:

2z^2+3z-14=0

(z-2)(2z+7)=0

z=-7/2