proyaop

First draw a graph, label the x-axis as "amount of uniforms ordered", and the y-axis as "amount of dollars"

Then you can plot the points (5, 66) and (8, 99), and make sure you make the y-axis 0, 33, 66, 99 so the graph isn't too tall.

Slope = (change in y)/(change in x) => (99 - 66)/(8-5) = 33/3 = 11.

If a line is parallel to another line, they must have the same slope:

y = -x/4 + b is the equation of the line.

Plug in -4, -7 as (x, y)

-7 = 4/4 + b

-7 = b + 1

b = -8

Equation of the line: y = -x/4 - 8

4) If angle DCB is x, then angle BDC is also x.

Angle DBC = 180 - 2x

Angle DBE = x - (180 - 2x) = 3x - 180 degrees

Angle EDB = 3x - 180

Angle BED = 180 - 2(3x - 180) = 180 - 6x + 360 = 540 - 6x degrees

Angle AED = 180 - (540 - 6x) = 6x - 360 degrees

Angle A = 6x - 360 degrees.

Angle B + Angle C + Angle A = 180 

x + x + 6x - 360 = 180

8x = 540

Angle BAC = 67.5 degrees

31f(6) = -119

f(6) = -119/31

119 + 31 = 150

Thanks melody!!!

Difference of cubes: (x - y)(x^2 + xy + y^2)

x^2 + y^2 = (x + y)^2 - 2xy

(x - y)((x + y)^2 - xy)

\((x - y)(100 - xy) = 504\)

How can you take it from here? Good luck.

\(z = a + bi\) where a and b are real numbers and i is one unit in the imaginary plane.

\(2(a + bi) + 3(a - bi) = -25 - 2i\)

\(2a + 2bi + 3a - 3bi = -25 - 2i\)

\(5a - bi = -25 - 2i\)

The real number parts of the equation are equal and the imaginary parts of the equation are equal:

\(5a = -25\)

\(-bi = -2i\)

Now, we can obtain that \(a = -5\) and \(b= 2\).

Thus, \(z = -5 + 2i\).

\(x + xy^2 = 250y\)

\(x - xy^2 = -240y\)

\(2xy^2 = 490y\)

\(xy = 245\)

\(x + 60025 = 250y\) 

\(x - 60025 = -240y\)

\(120050 = 490y\)

\(y = 245\)

x = 1, 1225

\(\sqrt{50y} + 2\sqrt{18y} = 2(\sqrt{8y} + \sqrt{72y}) - 5\)

\(5\sqrt{2y} + 6\sqrt{2y} = 2(2\sqrt{2y} + 6\sqrt{2y}) - 5\)

\(11\sqrt{2y} = 4\sqrt{2y} + 12\sqrt{2y} - 5\)

\(5 = 5\sqrt{2y}\)

\(1 = \sqrt{2y}\)

If you made a latex error and the y was outside the square root, \(y = {\sqrt{2}\over2}\). If not, then \(y = {1\over2}\).

The selling price was not 1.25x or 0.75x, it was the ending cost because if they made "25%" off of one of the gowns, the profit would've been 25$, the starting price wouldn't have been 1.25x... That's a logic flaw...

I would try to generalize the cost of the gowns with a variable, say --- "g"!

A 25% increase is 1.25 (1 + 25/100), so the final cost of one of the gowns would be 1.25g.

A 25% decrease is 0.75 (1 - 25/100), so the final cost of the other gown would be 0.75g.

Adding these two together, it gets 2g, which also happens to be the original cost of both:

Thus, as the result of these transactions, the percentage gain/loss = 0%