it seems to be common pracice to accept that the first line is the 0 line, so it is easiest just to ignore that one
the sequence is 2,4,8,16,32
I can just see that this is 2^n but if that is not immediately obvious to you, you can inspect it as a sequence.
since 4/2 = 8/4 = 16/8 = 32/16 = 2
this is a GP
the first term is 2 and the common difference is 2
\(T_n=ar^{(n-1)}\\~\\ T_n=2*2^{(n-1)}\\~\\ T_n=2^{(n-1+1)}\\~\\ T_n=2^n\)
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