Melody

In future please replace the latex with normal text.

Fun questions are always good.  Thanks SmartCookiezZ

one diagonal or both?

answered

At the beginning he had 66 blue + whatever number of blue ones that he gives away.

Let B be the number of Blue at the beginning

So initially he has B blue and  B+66 red

he gives away k of each so now he has

Blue:  (B-k)     and    Red:  B+66-k = (B-k)+66

We are told that he now has twice as many red so   B-k must equal 66

So    B=66+k

So he starts out with 66 blue plus the number of blue that he gives away.

So

if he gives away 5 of each then he starts with 66+5 blue and  132+5 red

if he gives away 20 of each then he starts with 66+20 blue and  132+20 red

i got    3sqrt2/8 cis 31pi/18

check

\(\frac{\sqrt3}{2}*\frac{\sqrt6}{4}=\frac{\sqrt{2*9}}{8}=\frac{3\sqrt2}{8}\)

What answer did you get?

Or better still, show me your working and I will tell you if it is correct.

I really do not know what you are after.  Maybe some info is missing?

but...

\(x^2+bx+(\frac{b}{2})^2=(x+\frac{b}{2})^2\)

The question is poorly written, the numbers do not make sense. 

It should have been written without the LaTex.