Melody

It would help if you included the address of the question that you want answered. 

The sum of the smallest two factors of an integer n is 6 and the sum of the two largest factor is 1122. Find n.

1 is a factor of every integer so the two smallest factors must be 1 and 5 which means that n is not divisable by 2 or by 3

The sum of the 2 largest factors is 1122.  So the number n must be smaller than 1122/2 = 561

So one is 561-x   and the other is 561+x

Maybe one is a multiple of 5           So maybe x=6t or 4t

x can't be 6t because 561 is divisable by 3 so 561*6t is also divisable by 3 which is not allowed.

What about x=4t

that would give us      561+4t    and   561-4t

I cannot see any obvious reason why this can't be true.  

I will try t values one at a time and see if I can find one that works

That one was easy, t =1 is a contender.

Well 565 does not have 2 or 3 as a factor and neither does 557 so they could be right.

557+565 = 1122

factor(565) = 5*113

factor(557) = 1+557

557*565 = 314705

So the number could be 314705

At this point in tme I am not convinced that this is the only possible answer though.

Hi Tom...riddle  

Wonderman is a pain BUT anybody who posts a question like that is in my veiw only interested in the quickest path to the answer.

i.e. they have the intention of cheating.

Sakath cannot even be bothered to present the question properly therefore I conclude he/she cannot be bothered to learn from any answer either.

Yes I spos, I just had not seen that before. 

Thanks SVS,

this is how I would attach this problem,

I had to look it up but I also have     2000 pounds in a US ton   .  

We have      \(\frac{x \;hours}{y \;pounds},\qquad \frac{2000\;pounds}{1\;ton}\qquad 1 ton,\qquad ?hours\\~\\ \)

I want   hours,   I want to cancel out all the other units.

\(\frac{x\;hours}{y\;pounds}\times \frac{2000\;pounds}{1ton}\times 1ton=\frac{2000x}{y}\;hours\)

Thanks Ginger,

That proof is so simple, I am glad you showed me.

I do not know. I didn't work it out to the end. I left that to you.

You have been accused many times, from one person anyway, of cheating.

I do not mind helping you to learn and to develop solving techniques but I don't intend to give you final answers.

Thanks guest

p.a.  is a normal term in my part of the world.  It means per annum.

Thanks guest,

Was this a coding question - I suspect it was.

If so you should have said so int the question.