kitty<3

If you mean what 100 and 3/2 equals, Enter it as 100 + (3/2)

$${\mathtt{100}}{\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{2}}}}\right) = {\frac{{\mathtt{203}}}{{\mathtt{2}}}} = {\mathtt{101.5}}$$

First off, do you mean 100 and 3/2, or 100 times 3/2, or something totally different?

Verify cot(x) * sec(x) = csc(x)

cot(x) = 1/tan(x)

tan(x) = sin(x)/cos(x)

So cot(x) = 1/ sin(x) * cos(x)

And sec(x) = 1/cos(x)

So the whole equation is:

1/ sin(x) * cos(x) * 1/cos(x) =csc(x)

The cos(x)  and 1/cos(x) cancel out:

1/sin(x) = csc(x)

csc(x) is the same as 1/sin(x):

csc(x) = csc(x)

:)

The calculator helps:)

$${\mathtt{\,-\,}}\left({\mathtt{0.5}}{\mathtt{\,\times\,}}-{\mathtt{113}}\right) = {\frac{{\mathtt{113}}}{{\mathtt{2}}}} = {\mathtt{56.5}}$$

This is the same as dividing -113 by -2.

  $${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}} = {\mathtt{25}}$$ :/

Para exponente, escriba ^

Por ejemplo, 4^2 es 4²

Si es un numero mayor que 3.50 y menor que 3.510, puede ser 3.501 o 3.502 o 3.503 o aún 3.5099999....

Divide todos los números de la lista por el número de cosas en la lista.

Por ejemplo, el medio de 1,2,3,4,5,6 es:

$${\frac{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}}\right)}{{\mathtt{6}}}} = {\frac{{\mathtt{7}}}{{\mathtt{2}}}} = {\mathtt{3.5}}$$

Escribe "asin(  "

You would first write this problem as an equation. Let's use x as the variable:

3x + (x - 2) + (x - 4) + (x - 6) + (x - 8) + (x - 10) + (x - 12) = 156

Simplify the equation by combining like terms (the x's and constants):

3x + 6x - 42 = 156

9x - 42 = 156

Add 42 to both sides:

9x = 198

Divide by 9:

x = 22

Now x represents the number of blocks in the bottom 3 rows. For the next 6 rows, just subtract two blocks from the row below it.

For example, the fourth row (from the bottom up) would be (x - 2) = 20 blocks.

The 5th row would be (x - 4) = 18 rows, and so on and so forth:)