kitty<3

Pulsa " = " otra ves para el resultado en notación científica.

You can plug this into a calculator: $$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\frac{{\sqrt{{\mathtt{3}}}}}{{\mathtt{2}}}}\right)} = {\mathtt{60^{\circ}}}$$

Or, you can use the unit circle (a circle with a radius of 1 which is very useful for finding exact values of angles with 30, 45, and 60 degree reference angles).

You would use the tangent of the angle to find the height of the flagpole, h.

Tangent is opposite/adjacent, and in this problem the opposite side is the height of the pole (h) while the adjacent side is the length to the pole's base (28).

Therefore: 

tan(38) = opp/adj

tan(38) = h / 28

Multiply both sides by 28.

$${\mathtt{h}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{38}}^\circ\right)}{\mathtt{\,\times\,}}{\mathtt{28}} \Rightarrow {\mathtt{h}} = {\mathtt{21.875\: \!997\: \!542\: \!196}}$$

The flagpole is approximately 21.88 m tall.

Dividing a number by a fraction is equivalent to multiplying that number by the fraction's reciprocal.

So sqrt(3) /2 divided by 1/2 is the same as sqrt(3) /2 multiplied by 2/1.

You can cross-cancel the 2s, since you are dividing by 2, then multiplying by 2.

= sqrt(3)/1

= $${\sqrt{{\mathtt{3}}}}$$

Hola,

NinjaDevo te ayudó con su sitios web, (thanks NinjaDevo:)

La tangente de un ángulo (x) en la trigonometría es: cateto opuesto (o) / cateto adyacente (a)

Entonces, la tangente de ángulo x es o / a

Escríbelos en paréntesis, como éste:

(1/4) = $$\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)$$

(1/4) / (1/4) = $${\frac{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)}{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)}} = {\mathtt{1}}$$

Es incorrecto escribirlo sin paréntesis: 1/4 / 1/4 = $${\frac{{\frac{{\frac{{\mathtt{1}}}{{\mathtt{4}}}}}{{\mathtt{1}}}}}{{\mathtt{4}}}} = {\frac{{\mathtt{1}}}{{\mathtt{16}}}} = {\mathtt{0.062\: \!5}}$$

Usa el arcoseno:

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{2}}}{{\mathtt{5}}}}\right)} = {\mathtt{66.421\: \!821\: \!521\: \!798^{\circ}}}$$

El ángulo ~66.422

$${\sqrt{{\mathtt{53.45}}}} = {\mathtt{7.310\: \!950\: \!690\: \!573\: \!695\: \!8}}$$

~ 7.31

Right, CPhill! That does make more sense for this problem:)

From the given information, you already know one point on the line, as well as the slope. 

Point: (0, 372)

Slope: -15

You can now find the function by using the point-slope formula: y-y₁ = m(x-x₁)

Plug in the point and the slope:

y - 372 = -15 (x-0)

Add 372 to both sides.

y = -15x + 372

So f(x) = -15x + 372