elevator starts at the top floor 372 feet and descends without stopping at constant rate of 15 feet per second. write a function that describes the height of the elevator after seconds
haha bottom ok first take the derrivative of the quatritac formula (ax2+bx+c) and multiply by the tangent of the parabolic curve.
+5478 From the given information, you already know one point on the line, as well as the slope.
Point: (0, 372)
Slope: -15
You can now find the function by using the point-slope formula: y-y1 = m(x-x1)
Plug in the point and the slope:
y - 372 = -15 (x-0)
Add 372 to both sides.
y = -15x + 372
So f(x) = -15x + 372
+130466 kitty<3...I like your answer, but I might suggest one small change.... how about this??
h(t) = -15t + 372 .... where "h" is some height after "t" seconds
Using "x" makes it seem as if there's some "horizontal" component to the problem...
Does this sound reasonable ?? (Who knows...I could be crazy !!)
