juriemagic

Thanx a lot Melody,

Like you said...this does make sense!. Thank you for your input!!

Thanx guest,

I agree 100%..Ta.

oops!!..then I guess that says a lot about me too!!!...lol.

Melody, yes, I certainly do understand what you are saying. Well, looking at this it certainly calculates to the correct answer. I kind of understand the principle behind this which was to take the first scenario and devide that by the 2nd scenario, making sure the unknown is at the bottom, meaning this:

${7 \over10}:{3 \over3}:{12 \over x}$

Then multiply the X out and put that equal to the rest. Multiply the top row and devide by the product of the bottom row.

anycase, I know you know what I'm saying, so it's not like I have to explain this to you..(sorry)..uhm, I think to really test this out would be to create a few different scenarious and try to calculate the unknown using this approach.

Thanx for being out there!! 

Hi guest,

I like your approach...thanx a lot!!

Hello Melody,

Thanx for the feedback!!

Okay, let me clarify this...

The paper reads:

GIVEN:

1)   AOIIQR

2)   PA = AQ

3)   PB = BT

Prove:

1) ABIIQT

2) O is the centre of the circle if PR is the centre line through the circle

3) BORT is a trapezium

Sorry if there was confusion, I did not realize giving it like it actually was on the paper would or could cause a mis-understanding. From my side, please accept my apologies.

haha...disects!!..oh my goodness!!!..so sorry, that was an honest boo boo...

Also, This exact question I found on the inernet in an exam question paper. The marks allocated for proving ABIIQT, was 2, and for proving the centre, also just 2. Sooo, I'm thinking going the similar triangle way is a lot of work for just 2 marks, HOWEVER, I do aknowledge that the approach given to me was far superior and most likely, the best approach.

Guys, you have all been a great help with this one, I really admire and love you all!!!

CPhill,

I really wish I had the experience you guys have!!..It's good to see how it's solved, however, please if you do not mind....what in my solution makes it wrong?..I understand my approach was wrong, simply because you say it was, and you gave me the appropriate solution....but why is my approach wrong?..would you kindly spend just a little more time please, and just educate me..please...I need to understand this?..You guys are great, thank you for being out there!!

Hi Melody,

well, honestly....I went about the whole thing a different way...The reason I believe I cannot make use of ratio's, is because I do not have any values. I do not know how one can use ratio's if there are no values....so I did this:

In triangle PQR:

AOIIQR     Given

PA=AQ     Given

Therefore AO runs through the middel of triangle PQR

Therefore AO devides PR     Midpoint theorem

Thus PO=OR

Since PR is the diameter,     Given

PO must equal OR

Thus "O" is the middle of the circle.

Is this wrong?..Thanx for your assistance!!

Hi guest,

thank you very much for nudging me into the right direction...I should be able to get this now...Thanx a lot!