ElectricPavlov

Point 1   (-1, -2)

point 2   (2,3)

(y₁-y₂₎ / ( x₁-x₂₎

(-2-3) / (-1-2) = -5/-3 = 5/3

How about:

sqrt(1) + sqr(4) + sqrt(9) + sqrt (16) + sqrt(25) = sqrt (225)  

For the first one, you are given two points....calculate the slope using this method:

https://web2.0calc.com/questions/what-is-the-slope-of-the-line-that-contains-the-points_1

For the second one,  the mid point will be given by the averages of the x and y values

 I'll do the 'x' one.....you do the 'y' one

 (x₁ + x₂₎   / 2 =  (1+5)/2 = 3   = x point of the midpoint.....now for the y:

?

yeppers!

200 (.99)    number of tetras originally    now subtrac x from that number

200(.99) - x       the TOTAL number of fish also gets decreases to 200 - x

The tetras remaining in the tank   200(.99) - x

    divided by the total number of fish  200- x   = 98 %

[200(.99) - x ] / (200-x) = .98     solve for 'x' the number of tetras to remove....  

1  Then you will have to add that percentage and the percentage 10000-14999 together

2 Correct

1   What about the portion of the circle labelled 'Under 10,000'   Isn't this less than 15000 too?

2   2 would be the people who take CALCULUS and statistics only.....we want Number theory and Statistics only.......?