ElectricPavlov

A Jerusalem

It is on the x-axis , so the y coordinate will be '0'

x, 0

Distance from point a=    sqrt ((-2-x)^2 + 0^2)

 equate to the distance from point b

         sqrt(0-x)^2 + (4-0)^2

x^2 +16 =  4 +4x + x^2

12 = 4x

x = 3

since y = 0    the point is     3,0    and the distance from each point is 5

ANOTHER method to indicate multiplication:

3 * 3   =   3 x 3  = 3 . 3  =  3(3)  

Here is one way:

tanr = sinr /cos r  = 5 cos q

sin r = cos r  5 cos q

pq/15  = pr/15   5  pq/15

1 = 5  pr/15

3 = pr      use pythag theorem to find pq = sqrt 216

    cos a = cos 90 = 0

This is very simialr to another of your posts....did you look at the way it was solved?

2 sin a = 3 cos a    divide both sides by 2   and cos a

sin a /cos a = 3/2

tan a = 3/2

sin a = 2 cos a     divide by cos a

sina / cos a   = 2

tan a = 2

There will be TWO values of x     one in the   III quadrant   and one in the IV quadrant 

arcsin (- .73 ) = -46.89 degrees ( or 313.11 degrees)    and   226.89 degrees

Volume occupied by TWO cones =   2    x  pi r^2  h/3

     = 2   * pi (12^2) (12/3) = 1152 pi    cm^3

Volume of cylinder = pi r^2 h

   = pi 12^2 (24) = 3456 pi    cm^3

Subtract the volume of the cones from the volume of the cylinder

     3456 pi -1152 pi= 2304 pi  cm^3                  = 7238.23 cm^3

That was just a typo    1.45 should be 1.75     or  1:45      answer does not change....when I calculated it I used 1.75   but I typed 1.45