Arrange the given parabola equation to vertex (h,k) form: y = a ( x- h) ^2 + k
by completing the square for x :
1/4 ( x^2 + 4x) +2
1/4 ( x^2 + 4x + 4) -1 + 2
1/4 ( x+2)^2 +1 Shows vertex = -2,1
the equation of a parabola in vertex form y=a(x−h)^2+k, ======> the focus is (h,k+1/4a)
focus is then -2 , 1 + 1/(4 * 1/4) = ( -2,2 )
and directrix is equal distance from the vertex as the focus and is y = 0