Shaded area is greater than the line....but does not include the line
find the equation of the line to be 2(x) + 1 so the shaded area is y > 2x+1 rearrange to 2x - y + 1 <0
10 + 24 = 34 miles If biking takes one hour and train takes one hour .
Natural numbers less than 3 include 2 1 and sometimes zero.
x^2 -12x + y^2 + 14y = C
(x-6)^2 + (y+7)^2 = C Circle centered at 6, -7
distance fomula to 10,1 is the radius
4^2 + 8^2 = d^2 = r^2
80 = r^2 C needs to equal 80
(x-6)^2 + (y+7)^2 - 80 = 0
You need to sample at least 2x the frequency to avoid losing data.....higher rates are better
2 x 7.25 kHz = 14.5 kHz sampling rate
14 500 samples per second and each requires 2048 levels 2048 = 2 11 So you need 11 bits to quantisize 2048 levels
14500 * 11 = 159500 bits per second 159.5 kbps or ~~ 1.6 x 102 kbps
Ooops....forgot it was sideways vertex is at (13.5,1.5)
Vertex form of the parabola is y = a ( x-1)^2 -6 sub in the point on the graph 3, -2 to calculate a
a = 1
y = (x-1)^2 -6 expand to
y = x^2 - 2x - 5 <===== you can finish from here I hope !
Re-arrange x = 2y^2 -6y + 18 this is a sideways parabola
arrange into vertex form
x = 2 (y^2-3y) + 18
x = 2 (y-1.5)^2 + 13.5 Vertex is at (1.5,13,5 )
sqrt 3 / 2 * AB = sqrt 3 / 2 * 8 = 4 sqrt 3
Add them = -45 n5
