ElectricPavlov

Pick an amount to finish with...say 100cc

x = x amount      100-x = y amount

.1x   +   .2(100-x) = .16 (100)

.1x + 20 - .2x  = 16

.1x  = -4

x = 40      then   y = 60        x:y is then  40:60  =  2:3

420.89 ft²

37.5%   ( or 3/8 ths)

Point - slope form of the line

(y- -3) = 2 (x-2)        y intercept ocurs when x = 2      sub that in to find y value

Initially

1/5 h = 3/7 j     re-arrange

h = 15/7 j

then

h -356 = j+428      sub in the red equation for h

15/7 j -356 = j+428        then you can solve for j      use this value to solve for h  

                                           then  subtract 356 from h  and add 428 to j ( the results should be the same)     and add them together..... 

When the ball hits the ground h = 0

0 = -16t^2+32t+128     Use quadratic formula to find t values....throw out negative value...

x = original salary

1.16 x  = new salary

1.16 x = 58 000

x = 58 000 / 1.16

2 big jars contain 0.3 kg more sugar 

than 3 small jars

     2b = 3s + .3

       re-arrange to   s =   (2b-.3)/3

5b + 2s = 8.35      total    now substitute in the red equation for 's'

5b  + 2(2b-.3)/3  = 8.35

b = 1.35 kg   per jar          now multiply by 5  (since there are 5 big jars).......

g/b = 8/7

g = 8/7 b

a = b + 4755       and     a = g + 4695      equate the 'a' definitions

b + 4755    =    g + 4695     now sub in the red equation

b + 4755    =   8/7 b  + 4695

b = 420      then   g = 480           <===== add together

 x^2 - 4x + y^2 - 6y - 36 = 14x + 2y     simplfy

x^2 -18x       +  y^2 -8y        = 36          'complete the square' for x and y

(x-9)^2         +  (y-4)^2         = 36 + 81 + 16

                                          = 133 = r^2                   r = sqrt (133)