ElectricPavlov

point slope form would just  be

( y-8) =  - 2 ( x-5)

origianlly nicole had 1 /(1+3) = 1/4 th   and hannah had  3/4 ths

then n added 4    and   h added 3       to cause   n to have  1/3   and h to have  2/3

1/4 x = n

1/4 x + 4  = 1/3 ( x + 4 + 3)

x = original amount of apples = 20        then hannah (at the end)  had   3/4 th 0f 20 PLUS 3 = 18 apples

OK...STOP re-posting this question with slight changes    !!

See here for solution:

https://web2.0calc.com/questions/applying-the-quadratic-formula-to-a-word-problem

Geez !

Did you post the other incorrect version of this ????????

d = 60    find s

60 = -.0056s^2 + .-14s

-.0056s^2 + .14s - 60 = 0     Quadrtaic Formula yields    s =    still yields imaginary numbers

      if you drop the negative sign in front of the s^2  you will get   s = 91.76 km/hr      

          ( the other incorrect posting of this question had  - .0065 s^2     this one (also incorrect) has - .0056s^2    )

yes

Data set A   1 444 6     median = 4   mode = 4   average = 4.6    range   1-6

Data set B   1 333 50   median = 3   mode = 3    average = 12    range = 1-50

= sqrt ( 60 * 12 * 63* 42 * x⁴)

= x² sqrt(190512)

=x² 252 sqrt(30)

g(x) would have to be of degree 8 for the sum of the two to be degree 8   ( since f(x) is only degree 5)

The area would be TWO complete circles' area + the area of the square

   cirlcel area = pi (d/2)^2               square area = side * side

 You should be able to take it from here .......

h = 2/5 p     This is given

then

h = (p-20) * 2      sub in the red equation

2/5 p  = 2p -40

-8/5 p = -40

p = 40 * 5/8 = 25   origianlly had paul

(1 - 3/4 - 4/7 ) x = 9

There is a mistake in this question     3/4 + 4/7 = ( 21+ 16)/ 28 = 37/28     which is greater than one...cannot be.