ElectricPavlov

You are welcome ! 

If one angle is 90   and the other two are the same....remember they all add to 180 for a triangle

   90   + angle  + angle  = 180

2 angle = 90

angle = 45 degrees

Infinite solutons for this as written..... part of it is missing....

Find angle K first    .... recall that all of the angles in a triangle sum to 180 degrees

Now that you have angle K      angle K and  JKL form a straight line = 180 degrees also

                                                         K + JKL = 180         then you can compute JKL

Sorry..... but if you get an account here on web2.0     you can message people  directly without posting on the forum page......   

Answer was shown in above post

        x - 2y -1 < 0     <=========  This is the form requested in the Q

You can calculat the slope betqeen the two lines   as   ( y1-y2) / (x1-x)      but the way this is drawn I think they want you to use

the   'rise over run ' method ( which is really the same thing )

     from the L poin to the R point       the rise  is   -2     the 'run' is 4     so rise/run = -2 / 4  = -1/2   which is the slope , m

slope intercept form of a line     y = mx + b      we found m = -1/2     'b' is the y -axis intercept at 4 (see it?)

                        so your line is    y = -1/2 x + 4     re-arrange to the requested form

                                                1/2x + y  = 4       multiply thru by 2 to get rid of the fraction\    

                                                  x + 2y   = 8       Done!

OK...here ya go ( image below)    Read carefully so you will understand .....

  Pick two convenient points on the line.....see the ones I picked?

   find the slope between these lines      slope = m = (y1-y2)/(x1-x2) =  (1-0) /( 3-1)   = 1/2

      so your line starts to look like    y = mx + b    <====== 'Slope-Intercept' form of a line

                                                        y = 1/2 x + b      now we need to calculate 'b'     use either of the points in the equation

                               using 3,1           1 = 1/2 (3) + b

                                                             b = - 1/2

                                       Now your line equation is  y = 1/2 x - 1/2

     the shaded area of the graph is everything GREATER than ( above ) the line

                               y > 1/2 x - 1/2     then re-arrange it into the form needed ( as I did in earlier post )  ......        helpful?

The graph is not loading......

Find the equation of the line.......Is this the problem you are having?