1. We start off with a length of 12 and a breadth of 10...so.....if we cut "x" off of both ends of these, each will be decreased by 2x. so the new legth will be 12 - 2x and 10 - 2x.
2. The surface area of the bottom willl be L x W = (12 - 2x)(10 - 2x) = 120 + 4x^2 - 44x.
The surface area of the sides will be....
2x [(12 - 2x) + (10 - 2x)] = 2x [ 22 - 4x] = 4x [11 - 2x]. = 44x - 8x^2.
So. adding these together...the expression for the total surface area is ... -4x^2 +120
3. The volume will be L x W x H = (12 - 2x)* (10 - 2x) *x = [120 + 4x^2 - 44x] * x = 4x^3 - 44x^2 + 120x
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1. Since we're adding 2 ft on each side, the total area is ...
(6x + 2 + 2) (x+ 2 + 2) = (6x + 4) (x + 4) = [6x^2 + 28x + 16 ] m^2
2. The area of the pathway is just the total area - the area of the garden =
[6x^2 + 28x + 16] - [(6x * x] = [6x^2 + 28x + 16] - (6x^2] = 28x + 16
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