We have two tasks here....choose the boxes....choose the b***s to go into those boxes...
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4 2 0
We have 3 ways to choose the first box......and we want to put 4 of the 6 b***s into it
3C(6,4) = 45
Then, out of the remaning 2 boxes, we want to choose one of the two to put the remaining two b***s into
So 45 x 2 = 90
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4 1 1
Agian we have 3 boxes to choose which 4 b***s out of 6 we put into it
So 3C(6,4)= 45 ways
And we have two ways to select the next box and two ways to select which ball goes into that box...
The last box and ball are defaulted
So we have
2C(2.,1) = 4 ways
So 45 x 4 = 180
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3 3 0
3 ways to choose the first box......and we want to choose 3 of 6 b***s to put into it
3C(6,3) = 60 ways
Then, we have 2 ways to choose the next box to place the remaining three b***s into
So 2 x 60 = 120 ways
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3 2 1
3 ways to choose the first box....choose 3 of 6 b***s to put into it = 60 ways
2 ways to select the next box and we want to choose 2 of the 3 remaining b***s to put into it
2C(3.2) = 6
Again, the last box and ball are defaulted
So 60 x 6 = 360 ways
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2 2 2
3 ways to select the first box .... choose 2 of 6 b***s to go into it = 3C(6,2) = 45
2 ways to pick the next box and choose 2 of the remaining 4 b***s to put into it
2C(4,2) = 12
The last box and remaig two b***s are defaulted
So 45 x 12 = 540 ways
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Anyway, that's what I get......!!!
