f(x) = 1 / √(9 - x^2)
Since the denominator can't = 0 , x cannot be 3 or -3. And since we can't take the square root of a negative number, any x values < -3 or > 3 make the square root non-real
So....the domain is just (-3, 3)
The range is a little trickier.....as "small" as y can be is when x = 0 ...and this is 1/3....and as x approaches either -3 or 3 in the domain, y approaches infimity...so, the range is [1/3, ∞)
Here's a graph.....https://www.desmos.com/calculator/9t9yvcfn2t
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