Here's the Calculus approach.........first, solve the volume in terms of h
300 = pi*r^2 *h
h = [300] /[pi*r^2] .......now....substitute this into the surface area "formula"
Sarea = 2pi*r^2 + 2pi*r*h
Sarea = 2pi*r^2 + 2pi*r* [300]/[pi*r^2]
Sarea = 2pi*r^2 + 600r^(-1) ....take the derivative with respect to r......
S' area = 4pi*r - 600r^(-2) .....set this to 0
4pi*r - 600r^(-2) = 0
4pi*r = 600r^(-2)
pi*r = 150r^(-2)
r^3 = 150/pi
r = (150/pi)^(1/3) = about 3.628 .....as Solveit found .......
And h = 300/ [pi * 3.628^2] = about 7.255
And the minimum surface area would be just as Solveit found......
