Very nice, Dragonlace.....I would have solved it using trig, but your approach is much simpler....!!!!
Thanks, misaki....
If x = √ y square both sides
x^2 = y
So
xy = x (x^2) = x^3
5) A is corect [multiply the circle with the radius of 3 * 4/3 = 4 ]
6) J is correct [multiply each of the given coordinates by 1.5]
No prob, Mathfordays.......
BTW....welcome.....!!!!!
Area of a trapezoid.....
Add the bases = 42 + 30 = 72
Divide this sum by 2 = 72/2 = 36
Multiply the last result by the height = 36 * 25 = 900 cm^2 = the area
Not too bad, huh???
A=7x+6 and A =4x +42
Since A = A, set these equations equal
7x + 6 = 4x + 42 subtract 6, 4x from both sides
3x = 36 divide both sides by 3
x = 12
And using either equation, A = 7(12) + 6 = 84 + 6 = 90
f(x)= x^2-x-4 and g(x) = 2x-4
Find g(8) and f(g(8)).
g(8) = 2(8) - 4 = 16 - 4 = 12
f (g(8) = f (12) =
(12)^2 - 12 - 4 =
144 - 12 - 4 =
132 - 4 =
128
3-3x6+2= -13
3 - (3 *6) + 2 =
3 - (18) + 2 =
3 - 18 + 2 =
-15 + 2 =
-13
We need to find the radius
2pi*r = 12pi divide both sides by pi
2r = 12 divide both sides by 2
r = 6
So the area = pi*(r^2) = pi (6^2) = 36 pi = about 113.1 square units
