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 #1
avatar+1018 
0

 

At a cafeteria, Mary orders two pieces of toast and a bagel, which comes out to 3.15.  Gary orders a bagel and four muffins, which comes out to 7.85.  Larry orders a piece of toast, two bagels, and three muffins, which comes out to 9.75.  How many cents does one bagel cost?  

 

wiseowl, what's up with the about a million postings?  Is this your homework or what?  

 

T is for toast  

B is for bagel  

M is for muffin  

 

                                         2T + B  =  315    (I'm using cents because the answer will be in cents.)  

                                         B + 4M  =  785  

                                         T + 2B + 3M  =  975  

 

from 1st equation              2T = (315 – B)   so   T = (315 – B) / 2   

from 2nd equation             4M = (785 – B)   so   M = (785 – B) / 4  

 

Now we have T and M in terms of B so substitute it into the 3rd equation.  

 

                                          (315 – B)           2B          3 • (785 – B)  

                                          ––––––––   +   ––––   +   ––––––––––  =  975  

                                                 2                  1                    4  

 

Let's get rid of those denominators by multiplying both sides times 4.  

 

                                           2 • (315 – B)  +  4 • 2B  +  1 • 3 • (785 – B)  =  4 • 975   

 

Multiply it out                       (630 – 2B)  +  8B  +  (2355 – 3B)  =  3900  

 

Combine like terms              3B  =  915  

 

                                              B  =  305  ......  One bagel costs 305 ¢  

 

Plugging into original equations, a toast costs 5¢ and a muffin costs 120¢ 

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28.10.2023
 #1
avatar+1018 
+1

 

Will and Grace are canoeing on a lake.  Will rows at $50$ meters per minute and Grace rows at $30$ meters per minute. Will starts rowing at $2$ p.m. from the west end of the lake, and Grace starts rowing from the east end of the lake at $2{:}45$ p.m. If they always row directly towards each other, and the lake is $2800$ meters across from the west side of the lake to the east side, at what time will the two meet?   

 

Will has a 45 minute head start, so he's already traveled (45 min)(50 m/min) = 2250 m  

before Grace even begins to row.

 

So, the actual distance of closure for Will and Grace is (2800 m) – (2250 m) = 550 m  

 

rate times time equals distance  

 

Since they meet, they will both row the same amount of minutes.  Call it t.  

 

Therefore, the setup is                (50)(t) + (30)(t)  =  550  

 

                                                                       80t  =  550  

 

                                                                           t  =  550/80  =  6.875  

 

The 6 is minutes and the .875 is the fraction of a minute  

(60 sec/min)(0.875 min) = 52.5 sec ... let's round that to 52 sec   

 

So the clock time they meet is 6 min 52 sec after Grace starts.

 

Grace started at 2:45, so add 6 min 52 sec and the clock will read 2:51:52 pm when they meet  

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28.10.2023