Let A be the number of adult tickets and C be the amount of children tickets. We can form the equation 105A + 60C = 7155, as we converted it from dollars to regular integers. We can simplify the equation by dividing by 5, giving 21A + 12C = 1431. Dividing by 3 gives 7A + 4C = 477. 477 divided by 7 gives 68 remainders 1, and if we remove one more seven and add it to one, we will have a multiple of 4. This means 67 adult tickets and 2 children tickets.