This 3d graph should help:
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One way as follows:
\(\frac{3-\sqrt x}{9-x}=\frac{3-\sqrt x}{(3-\sqrt x)(3+\sqrt x)}=\frac{1}{3+\sqrt x}\)
Hence limit as x tends to 9 is 1/6
"A 8-foot tall stop sign creates a shadow that is 2 feet long. At the same time, a utility pole creates a shadow that is 9 feet long. How tall, in feet, is the utility pole?"
h/9 = 8/2
h = 8*9/2 ft or h = 36 ft
..
\(\sqrt{18b^5}\times\sqrt{2ab}\rightarrow\sqrt{36}\times\sqrt{b^6}\times\sqrt a \rightarrow6b^3\sqrt a\)
Although your final value of 4.21m/s is correct GingerAle, you might want to check the values involved under the square root sign!
Try typing in
Solve(x-y/2, x+y-3/2) and press = or Enter
You should get the solution to the two simultaneous equations
x - y/2 = 0
x + y = 3/2
9x - 28 = (6x + 2)
3x = 30
x = 10
RSV = 9x - 28 → 62º
There are seven rectangular sections, each of area 1, and seven curved sections each of which form one seventh of a sector of a unit circle. Hence the area of S is 7 + 7*pi*12/7 or S = 7 + pi
Answers to questions 2 to 5:
Constant acceleration kinetic equations can be used, as follows:
+33665 
