Anmelden
Login
Benutzername
Passwort
Login
Passwort vergessen?
Rechner
Forum
+0
Formeln
Mathematik
Hilfe
Komplexe Zahlen
Integralrechnung
Differentialrechnung
Gleichungen
Funktionsgraphen
Lineare Algebra - Vektoralgebra
Zahlentheorie
Prozentrechnung
Standard-Funktionen
Wahrscheinlichkeitsrechnung
Trigonometrie
Einheiten-Umrechnung
Rechnen mit Einheiten
Über Uns
Impressum
Datenschutzrichtlinie
Nutzungsbedingungen
Credits
Google+
Facebook
Email
web20calcnoob
Benutzername
web20calcnoob
Punkte
16
Membership
Stats
Fragen
1
Antworten
4
2 Questions
4 Answers
0
462
1
+16
The spherical coordinates of $(-3, 4, -12)$ are $(\rho, \theta, \phi)$. Find $\tan \theta + \tan \phi$.
The spherical coordinates of $(-3, 4, -12)$ are $(\rho, \theta, \phi)$. Find $\tan \theta + \tan \phi$.
●
web20calcnoob
06.08.2020
0
857
1
+16
i think i got part a down $$z^2 - 2(x)(z)cos(\theta) + (x^2 - y^2)= 0$$ I need help with part b
In most geometry courses, we learn that there's no such thing as "SSA Congruence". That is, if we have triangles $ABC$ and $DEF$ such that $AB = DE$, $BC = EF$, and $\angle A = \angle D$, then we cannot deduce that $ABC$ and $DEF$ are congruent. However,
mehr ..
●
web20calcnoob
17.07.2020
#1
+16
0
the answer is 40 degrees
web20calcnoob
21.07.2020
#1
+16
0
the answer is 672
web20calcnoob
21.07.2020
#1
+16
+1
the answer is 0
web20calcnoob
21.07.2020
#1
+16
0
the answer is 7
web20calcnoob
17.07.2020