Vinculum

I got it!!!!!!

I forgot to type in the pi...

Its pi/4!!!!

Thank you for the answer CPhill, it still seems to be wrong...

I put my work below, to show what I got before

Im still confused on what is wrong ...

Original post: https://web2.0calc.com/questions/consider-rhombus-abcd-with-side-length-6

My work: 

I got that the circumference would be 6, so the area of the base would be 9. Then, I got that the height is 3/2 because 9*3/2 = 27/2. But, when I typed in 1/4 for the answer which is (3/2)/6 it was wrong.

 lol

sure

Yep!!!!

Here is my cake for you!!!!!

Happy Birthday Melody!!!!!!!!

Using the quad formula:

$\frac{-\left(-11\right)\pm \sqrt{\left(-11\right)^2-4\cdot \:5\cdot \:4}}{2\cdot \:5}$

$\frac{\left(11\right)\pm \sqrt{41}}{10}$

Substituting this into $\frac{1}{a}^2\:+\:\frac{1}{b}^2.$

$\frac{1}{\frac{\left(11\right)\pm \:\sqrt{41}}{10}}^2\:+\:\frac{1}{\frac{\left(11\right)\pm \:\sqrt{41}}{10}}^2$

= $\frac{81\pm11\sqrt{41}}{16}$

or 

approx. 9.46464646464 and 0.66035

-Vinculum

That is true, 

You seem to get these counting and prob questions with ease. These type of questions always mess up my brain!!!

-Vinculum