Find x, y, and z such that x3+y3+z3=k, for each k from 1 to 100
Yikes. I feel bad for you, you gotta do some hard math, Mr. Guest.
I think you can do some rooting.
x+y+z=\(\sqrt[3]{k}\)
Other than that, I have 0 clue on how to keep going.
Yay!
Process of elimination.
The first one doesn't make sense, it's like cutting a giant hole in the back of a sweater.
Second one the long lanky things are hugging the shape-oid thing.
Third one you might get wrong but if you notice, it says six for the side panel ones.
So, it's D.
I don't think that is correct...
Shouldn't it be
2*(30/6)=10?
EDIT: oh no ep has been typing for quite a while i might get embarrassed.
EDIT 2: OH GOD NOW CPHILL IS HERE IMMA GET FLAMED
I'm literally so sad that I missed that.
132 is 169
Each triangle is 7.5*16=120
120*4=480
480+169=649
EDIT: did my math wrong lul, try the one either below or above mine
I don't understand what you want us to find. Is it x and y, or the radius and center.
-3 -108 -234 -384 -564 -783 -1053
×2-102 ×2-18 ×2+84 ×2+204 ×2+345 ×2+513
ow my thumbs
20! is 2432902008176640000
The first digit of 20! is 2
Which is 2000
Well you could split it up into squares of 16. Which would be the longer, but easier way.
There are two 8x8 squares.
64+64=128
128+16+16+16+16+16=208
