TaliaArticula

Hey there, Guest!

So, let's solve this:

$x^5=-x^3$

Step 1: Subtract -x^3 from both sides.

$x^5−(−x^3)=−x^3−(−x^3)$

$x^5+x^3=0$

Step 2: Factor left side of the equation.

$x^3(x^2+1)=0$

Step 3: Set factors equal to 0.

$x^3=0$ or $x^2+1=0$

Therefore, our answer is x=0.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Guest!

So, simplifying.

128p^13q^17

And that's your answer.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Chocolatehere!

FYI, this question has already been answered here: https://web2.0calc.com/questions/find-all-complex-numbers-z-such-that-z-4-4-note-all

So that's that.

Now have some chocolate. 🍫

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Guest!

So, let's solve this.

$-8x^2y^4z^3+12x^4yz^3-2x^2yz^5$

$−8x^2y^4z^3+12x^4yz^3−2x^2yz^5$

= $2x^2yz^3(−4y^3+6x^2−z^2)$

And there we have our answer.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Guest!

So, let's get to it:

$\frac{(6m-5)}{(2m^2-m-6)}+\frac{(2-3m)}{(m^2-4)}$

$\frac{2m^2-8m+8}{2m^4-m^3-14m^2+4m+24}$

$\frac{2(m-2)(m-2)}{(m+2)(m-2)(m-2)(2m+3)}$

$=\frac{2}{2m^2+7m+6}$

And there's our answer.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, ellapow!

So let's solve this problem.

$\left(-1\right)^2+5\left(-1\right)-6$

$1+(5)(−1)−6$

$1+−5−6$

$−4−6$

$x=-10$

Therefore, x equals -10.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Guest!

This question has already been answered here: https://web2.0calc.com/questions/please-help_66642#r2

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Guest!

So, let's solve your problem:

Step 1: Simplify both sides of the equation.

$n^2=n^2+4n+4$

Step 2: Subtract n^2 from both sides.

$n^2−n^2=n^2+4n+4−n^2$

$0=4n+4$

Step 3: Flip the equation.

$4n+4=0$

Step 4: Subtract 4 from both sides.

$4n+4−4=0−4$

$4n=−4$

Step 5: Divide both sides by 4.

$\frac{4n}{4}=\frac{-4}{4}$

Therefore, n=-1.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Guest!

So the missing number is 0.001.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Hey there, Guest!

So the perimeter is 22 units.

Here's a graph to help you count: https://www.desmos.com/calculator/egnumghnxs

Hope this helped! :)

( ﾟдﾟ)つ Bye