fixed
sand is better.
dirt consists of lots of organic matter which tends to trap the water into tiny pools
in good sand the water spreads homogeneously through it and maximizes the surface area of the exposed water
(I work at a horse rescue. This winter we're all too familiar with the drainage (and lack thereof) of even mildly polluted sand)
\(f(x) = a x^6 - b x^4 + x - 1\\ \text{little trick here}\\ f_e(x) = a x^6 - b x^4 - 1 \text{ (this is the even part of }f(x))\\ f_e(x) = f_e(-x)\)
\(f(x) = x + f_e(x)\\ f(2) = 2 + f_e(2) = 5\\ f_e(2) = 3\\ f(-2) = -2 + f_e(-2) = \\ -2 + f_e(2) = \\ -2 + 3 = 1\)
\(\dfrac{A}{x+3}+\dfrac{6x}{x^2+2x-3}=\dfrac{B}{x-1}\\ \dfrac{A}{x+3}+\dfrac{6x}{(x+3)(x-1)}=\dfrac{B}{x-1}\\ \dfrac{A(x-1)+6x}{(x+3)(x-1)}=\dfrac{B(x+3)}{(x+3)(x-1)}\)
\((A+6)x-A=Bx + 3B\)
\(A+6 = B\\ -A = 3B\\ \text{Solve these two equations for }A, B\)
\(\text{Ok, my response didn't really apply. I misunderstood what they wanted}\\ V = 250(1.28)^d\\ V = 250(1.28)^{\frac {t}{10}}\\ V = 250\left((1.28)^{\frac{1}{10}}\right)^t\\ V = 250(1.025)^t\)
\(a^t = e^{\ln(a)t}\)
are there missing decimal points?
\((f.g)(x) = f(x) g(x)\\ \text{so just multiply the two polynomials together}\)
You don't need help. You're just lazy.
Make a table of values for f(x), and one for g(x)
compare them
If you need to zoom in on an area where they are close but not exactly equal and use closer values of x to find equality, do so
\(f(x) = 4x^2 + 6x = 2x(2x+3)\\ \text{If this problem makes any sense at least one of these terms will be a factor of }g(x)\\ g(x) = 2x^2 + 13x + 15 = (2x+3)(x+5)\\ (f/g)(x) = \dfrac{f(x)}{g(x)} = \dfrac{2x(2x+3)}{(x+5)(2x+3)} = \dfrac{2x}{x+5}\\ \text{HOWEVER}\\ \text{There is a values of }x \text{ for which this is invalid}\\ \text{I leave it to you to identify these}\)
+6252 