I am not a super smart mathematician (I'm in 9th grade), but I think I found the area of a tesseract.
Divide 980 by 2.
980/2=490
I can tell you the volume of the enclosed space in a hypersphere, but any others you may have to find on your own.
\(V={1\over2}\varpi ^2R^4\)
^
That is actually this: π
There is no solution.
\(3x+4*{-3\over4}x-2=20\)
Simplify.
\(3x-4*{3\over4}x-2=20\)
Simplify
\(3x-3x-2=20\)
Combine like terms.
\(-2=20\)
The only problem with that answer is that it is incorrect, so therefore x has no solution.
! means factorial.
Ex. 4!=1*2*3*4
9=10 is an incorrect statement because 9 does NOT equal 10.
2m^-4/(2m^-4)^3 = 0.25[(m)^8]
You have 1/24x3.
1/(24x^3)=x = {x=((i)/24^((1/4))), x=-((1/24^((1/4)))), x=-(((i)/24^((1/4)))), x=(1/24^((1/4)))}
sqrt(200)/2 = 7.0710678118654752
Beat me to it.
