Letxbe the fraction of the swim team that are sophomores. Then, the fraction of the swim team that are freshmen is1−x.

We are given that the probability that a sophomore is elected is4/7times the probability that a freshman is elected. This can be expressed mathematically as follows:

P(\text{sophomore}) = 4/7 \cdot P(\text{freshman})

We are also given that each member is equally likely to be elected, which means that the probability of a sophomore being elected is equal to the probability of a freshman being elected plus the probability of a sophomore being elected. This can be expressed mathematically as follows:

P(\text{sophomore}) = P(\text{freshman}) + P(\text{sophomore})

Substituting the first equation into the second equation, we get:

4/7 \cdot P(\text{freshman}) = P(\text{freshman}) + P(\text{sophomore})

Combining like terms, we get:

3/7 \cdot P(\text{sophomore}) = P(\text{freshman})

Dividing both sides byP(freshman), we get:

3/7 \cdot x = 1-x

Solving forx, we get:

x = \frac{7}{10}

Therefore, 7/10 of the swim team are sophomores.