Your goal is to get x all alone.
Even i had trouble and still do with these equations, but every time you get rid of something you have to think of the consequences that's why you should take away the small things so that the equations is closer to x and its less complicated.
In the coding, i have shown what i added or took away.
Look at that and speak to me after if you're still having trouble answering it.
When i added 9x if instead +2x i would have gotten a negative but it's still right and i still would have gotten an answer.
$$\begin{array}{rrl}
33-2x&=&5-9x\qquad(- 5)\\
28-2x&=&-9x\qquad(+2x)\\
28&=&-7x\qquad(28\div(-7)=-4)\\
x&=&-4\\
\end{array}$$
Also correct!
