Each number has a 1/70 chance of being picked per year, so honestly there is no number with higher probability to be picked (get other sources just in case I'm wrong...)
I'll give a simple answer, cause i'm lazy.
520 ppl voted for Emmanuel and 480 ppl voted for Marine.
If that is the total population of Froggyville, then yes, Emmanuel has a very high probability of winning. But if not, then Marine still has a chance.
as i said, im lazy
Those #s tho
Thank you.
Equilateral triangle radius of circumcircle = \(\frac{s}{\sqrt{3}}\)
Which means \(r = 3\sqrt{3}\)
Area of a circle is Pi*r^2
Substitute to get \(\Pi ({3\sqrt{3})}^2\)
Which is equal to \(27\Pi\)
The area of the circumcircle is \(27\Pi -units^2\)
I agree, but my visualization of infinity in this theory is the amount of possible numbers, or in this case, numbers, decimals, and fractions.
Thanks for your opinion!
I'm visualizing the concept of infinity as the theoretical "number" of possibilities for a number or decimal, or "numerical infinity".
But I agree with you
What about them, exactly?
First, how much water is in the aquarium? If it is not mentioned, it's impossible to solve.
735.
600 < 735 < 700
7-odd 3-odd 5-odd
7+3+5=15
+349 
