kitty<3

$${\sqrt{{\mathtt{441}}}} = {\mathtt{21}}$$

*While -21 is also a square root of 441, the principal square root is positive 21.

(-5/7) divided by (-18/35)

Is the same as (-5/7) * (-35/18)

Multiply the numerators and denominators:

= (-5 * -35) / (7*18)

= 175 / 126

Divide both numbers by 7 to simplify:

= 25/18 or ~ 1.3888...

Enter "sqrt(2.02,5)" into the site calculator:

$${\sqrt[{{\mathtt{{\mathtt{5}}}}}]{{\mathtt{2.02}}}} = {\mathtt{1.150\: \!986\: \!616\: \!874\: \!657\: \!5}}$$

Once you get the answer, press "Enter" again and the calculator will write it in scientific notation:)

First find the square roots of 144, which are 12 and -12.

So now you know that the square of any integer less than 12 and greater than -12 would be less than 144.

That includes:

0, ±1, ±2, ±3, ±4, ±5, ±6, ±7, ±8, ±9, ±10, ±11

Which would be 23 integers, including zero.

$${f}{\left({\mathtt{x}}\right)} = {{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{7}}$$

Plug in -3 for x:

$${f}{\left(-{\mathtt{3}}\right)} = {\left(-{\mathtt{3}}\right)}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}\left(-{\mathtt{3}}\right){\mathtt{\,-\,}}{\mathtt{7}}$$

Now simplify:

$${f}{\left(-{\mathtt{3}}\right)} = {\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{7}}$$

$${f}{\left(-{\mathtt{3}}\right)} = {\mathtt{11}}$$

Since 1 kg = 2.20462 lb, set up a conversion: 

 3.18kg * (2.20462 lb/1kg)

= $${\mathtt{3.18}}{\mathtt{\,\times\,}}{\mathtt{2.204\: \!62}} = {\mathtt{7.010\: \!691\: \!6}}$$

~ 7.01 lb

5 1/3 - 3 7/8

Escríbelo con paréntesis en la calculadora:

(5+(1/3)) - (3+(7/8))

= (16/3) - (31/8)

= (16/3) *(8/8) - (31/8) *(3/3)

=(128/24) - (93/24)

= (35/24)

= $${\frac{{\mathtt{35}}}{{\mathtt{24}}}} = {\mathtt{1.458\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

Usa el teorema de Pitágoras:

$${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

Por ejemplo:

16 es $${\mathtt{a}}$$ y 10 es $${\mathtt{b}}$$. d es la diagonal $${\mathtt{c}}$$.

$${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

$${{\mathtt{16}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{10}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

$${\mathtt{256}}{\mathtt{\,\small\textbf+\,}}{\mathtt{100}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

$${\mathtt{356}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

$${\mathtt{c}} = {\sqrt{{\mathtt{356}}}}$$

$${\mathtt{c}} = {\sqrt{{\mathtt{356}}}} \Rightarrow {\mathtt{c}} = {\mathtt{18.867\: \!962\: \!264\: \!113\: \!207\: \!6}}$$

Preguntas log(10) -8 o log (10-8)?

Si es log(10)-8:

log(10)-8

= 1-8

= -7

Si es log (10-8):

= log(2)

= $${log}_{10}\left({\mathtt{2}}\right) = {\mathtt{0.301\: \!029\: \!995\: \!663\: \!981\: \!2}}$$