Jtbreezii

Thank you!! I started to understand more of how you came up with this formula. I really appreciate your help!! I have definitely taken on something I need help with. I am going to have to find a tutor or someway to get help for this course. I am more than willing to put the time in to learn. Ive been putting time in but im not getting it. Cant believe that guy is bullying me because im reaching out for help!! We should build each other up!! Thank you for all your help.  

Where do you get 9.85??

If I can get this assignment done im getting a tutor!! Any online suggestions would be greatly appreciated!!

Im sorry I still dont understand!! Can you please explain how you got that. I have a assignment due every week in this class and its online. Ive took many online classes but i now know cant teach myself Math :/ 

Thank you!! I see where I went wrong but im still honestly confused. I really do appreciate your help!! I will not be taking anymore online math courses after this!! In class Math ONLY for me :)

Could you help me with this please..  Its practicing with binomial distribution

A company has determined that 1% of the parts it makes are defective. If the company packs a shipment of 5 parts to a customer, what is the probability that : 

a) none are defective 

b) more than 2 are defective

I have been searching for help online and found a similar question where i came up with these answers

P(defective) = 1-0.05 

a) = 0.95

2- 0.95 

b) = 1.05

I feel like im atleast in the right direction but honestly still dont understand.. :/ 

Thank you for the heads up!! I greatly appreciate it!! With your help this is what I come up with...

P(defective) = 1-P(defective)

E(profit) = P(defective) · $350 - P(defective) · $700

P(defective) = 1 - 0.025 = 0.975

E(profit) = 0.975 · $350 - 0.975 · $700

                           $341.25 - $68.25 = $273

E(profit) = $273