Johnkemper

First, convert each number from base 12 to base 10:
2A31₁₂ = 2×12³ + 10×12² + 3×12¹ + 1 = 3457₁₀
B75₁₂ = 11×12² + 7×12 + 5 = 1709₁₀
88₁₂ = 8×12 + 8 = 104₁₀

Now multiply them in base 10:
3457 × 1709 × 104 = 614,372,752

Now convert 614,372,752 back to base 12. The result is:
62B5B6A8₁₂

So, the answer in base 12 is 62B5B6A8₁₂.

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