jimkey17

Yeah, so there isnt any good way except taking off their own hats, lol. Or write down the color of the 2 other people's hats on the wall.

So there are 25 ways to pick the first, 16 for the second, and 9 for the third.

In total there are 25*16*9/6=600 sets. 

sin(34.75)=0.57

v=34.75

Hello Guest!

Apparently, I cant load your asymptome graph because it is incomplete. Would you please add the rest of the graph so I can reply? Thank you.

Just take off their own hat, lol.(jk)

Or tell another prisoner what color their hat is.(If you can)

I don't know an exact solution but those are my guesses.

Your welcome.

The sparse subsets of {1} are {} and {1}, so there are 2 subsets of {1}.

The sparse subsets of {1,2} are {}, {1}, and {2}, so there are 3 subsets of {1,2}.

The sparse subsets of {1,2,3} are {}, {1}, {2}, and {3}, so there are 4 subsets of {1,2,3}.

The sparse subsets of {1,2,3,4} are {}, {1}, {2}, {3}, {4}, and {1,4} so there are 6 subsets of {1,2,3,4}.
 

The sparse subsets of {1,2,3,4,5} are {}, {1}, {2}, {3}, {4}, {5}, {1,4}, {1,5} and {2,5} so there are 9 subsets of {1,2,3,4,5}.
 

We found a pattern! The number of sparse subsets of {1,2,3, ... ,n} is the number of subsets of {1,2,3, ... ,n-1}+{1,2,3, ... ,n-3}. So the number of subsets of {1,2,3, ... ,12} is $\boxed{\text129}$.

is this an ad?

Well just learn more spelling and words do some over your grade like what I do

so it is y=[slope]x+[y-intercept] so the equation is y=-2x-8

It's becuase the LaTeX box isn't working:

$\LaTeX$

(Not working) it eventually comes out as $\LaTeX$ 

we have -1^2-2*-1=1--2=3 so f(-1)=3

cube=x^3

squrae roots=√x

x^3/√x=x^6

I think It's 12^2=144 am I right?

we see that y+3x=180 and 3y=180 so y=60 and 3x=120 so x=40 and 2x+6y=80+360=440 so 2x+6y=(D)440

so the mean is (0+99)*100/2=4950 then 4950/100=49.5 so the mean is 49.5

Thanks