\(\displaystyle g(x)=\sqrt[3]{\frac{x+3}{4}}\), for what value of x will g(2x) = g(x)? x=0
\(\frac{a}{b} = \frac{3}{5}, \frac{b}{c} = \frac{6}{15},\space and\quad \frac{c}{d} = \frac{1}{6}. \ \textcolor{red}{What \ is \ the \ value \ of \frac{a}{d}}?\)
Explain.
Why did you like your comment when you got it wrong?
\(\displaystyle \int_{0}^{3} x^2 dx = 3^2 - 0, \mathrm{which\space is} \ \textcolor{red}{9}\), so the area under the curve from 0 to 3 is 9.
simplify the parenthesis, then solve the 3 step equation.
nice
$\displaystyle \frac{3-z}{z+1} \geq{1}$
I think both of you guys messed up :)
This honestly should be posted in the sticky topics (in my opinion
wow thanks! I really never heard of it!
bro.
No I was the asker and your answer was incorrect, chill.
I mean it could be him just not signed in :shrug:
+280 