HighSchoolDx

*sorry, i meant the first function. The second seems to intersect a few more times, but I'm not sure whether to count the intersections of each of the pieces with the third individually, or as a whole. i.e. individually, there would be around 2007*2 intersections, yet as a whole it would be around 2007.

GREAT SOLUTION

Note the entire expression is 2(a + b), so substitution gives a^2 - b^2 + 3a + b = -2.

THANK
THATS ONE ELEGANT SOLUTION!

BIG BRAINS 

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THIS IS BIG BRAIN TIME! ANOTHER WAY OF GETTING> THE SAME ANSWER

YOO NOW i get it! Thank you for the edit CPHILL :)

THANK YOU!!!!!!!'

I am stuck on this step: why will p/q = 1/10 imply  q = (1/10) p?

i'll try to figure it out now. p/q = 1/10. so 10q = p. so q = p/10 which is (1/10) p FIGURED IT OUT

Wait... it's p/q =1/10. so it is 10p = q???? so then p = (1/10) q

OOPS! I misread your problem and thought the 5 was a 2.

For this problem with 1500, it is still similar. 55562 and 35554 are there, so it is 5! / 3! and 5! / 3! = 20 and 20. 20 + 20 = 40

https://web2.0calc.com/questions/in-triangle-and-let-be-the-incenter-the-incircle

(again)