Hephaestus

\(S_1*S_2 = 80\)

\([S_1+1]*[S_2-1] = 90\)

\(S_1 = {80\over S_2}\)

\([{80\over S_2}+1]*[S_2-1]=90\)

\([{80+S_2\over S_2}]*[{S_2-1\over 1}]=90\)

\({{80S_2-80+(S_2)^2-S_2}\over S_2}=90\)

\({{80S_2-80+(S_2)^2-S_2}} =90S_2\)

\({{80S_2-80+(S_2)^2-S_2-90S_2}} =0\)

\({-80+(S_2)^2-11S_2} =0\)

\((S_2)^2 -11S_2-80 =0\)

\(S_2=16\)

\(S_1 = 5\)

\(p = 42\)

_{graph 1:}

\(V= {[(15)5]22}+[(5^2)22]\)

\(V = 2200\)

_{graph 2:}

\((8*14*5)+({8\over2}^2)\pi \)

\(V = 1263.7\)

\(ratio_1= 11:24\)

\(class={school\over 20}\)

\(school = {class[20]}\)

\(ratio_1 = 220:480\)

_Total:

\(220\)

\(5,688,286,422\)

\(T_b = T_s[60]-T_g[21]\)

\(T_b = 39\)

\(J_b= T_b[39]-S_b[20]\)

\(J_b = 19\)

\(J_g = T_j[34]-J_b[19]\)

\(J_g= 15\)

_Answer:

\(15\)

\({-{1\over 2}}= {{1\over 2}\over{1-{1\over 2}}}\)

₌

\(-{3\over 2}\)

\(A_Q ={1\over5}AB\)

\(Arc[AP]= {1\over 5}Arc[AB]\)

\(PQ = { \sqrt{(P_O)​​^2-(AB)​​^2}}\)

\(PQ = 4\)

\(PB = {\sqrt{​​(PQ)^2+(QB)^2} }\)

\(PB =\sqrt{80}\)

_R:

\(PB = {4\sqrt{5}}\)

_If \(FG\) ₌ \(FR\), _Arc \(FG\) _{= Arc} \(FR\).    

\(FQ = 28°\) 

_Total:

_{\(360-[2(130°)+28°]= \angle RPG\)}

_{\(\angle RPG = 72\)}